CBSE Class 12 Mathematics Board Paper 1 — MCQs with Answers
Original paper · CBSE patternWritten by our subject team, not a reprint of an official sample paper.
- Questions
- 20
- Time
- 30 min
- Marking
- +1, no negative marking
- Mix
- 4 Easy · 8 Medium · 8 Hard
Board Paper 1 — CBSE Class 12 Mathematics is a full 20-question objective paper for Class 12 Mathematics, written in the CBSE board pattern and marked the way the board marks: +1 for a correct answer and 0 for a wrong one — no negative marking, exactly like the real board paper. It follows Section A of a real CBSE paper. Q1–Q16 are MCQs with one correct answer. Q17–Q18 are case-based questions on a short source. Q19–Q20 are assertion–reason questions that use the board's own four answer options.
It is set a little harder than the real board paper on purpose (4 Easy · 8 Medium · 8 Hard), because a paper you find easy tells you nothing about exam day. You get 30 minutes, about 90 seconds a question, which is the speed the real paper needs. 8 of the questions are solved in full below, each with the correct option and a worked explanation. Sign in free to attempt the other 12, timed and scored.
Take it like a real exam, with your books closed. Your score on a timed full-length paper is the only honest way to know if your Mathematics revision holds up across all the chapters. That is exactly what the board tests, and chapter-wise practice cannot tell you.
8 solved questions from this paper
Answer and worked explanation shown for each. The remaining 12 are timed and scored when you sign in free.
- Q1Easy
On the set A = {1, 2, 3}, the relation R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)} is:
A.reflexive but neither symmetric nor transitive✓ CorrectB.reflexive and symmetric but not transitiveC.reflexive and transitive but not symmetricD.an equivalence relationAnswer: A. reflexive but neither symmetric nor transitive
Explanation: Reflexivity holds because (1, 1), (2, 2) and (3, 3) are all present. Symmetry fails since (1, 2) belongs to R while (2, 1) does not, and transitivity fails since (1, 2) and (2, 3) are in R but (1, 3) is not. Assuming a reflexive relation automatically carries symmetry is the usual slip.
- Q2Easy
If A is a square matrix such that A² = A, then (I + A)³ − 7A equals:
A.AB.I✓ CorrectC.I + AD.2AAnswer: B. I
Explanation: Since I commutes with A, (I + A)³ = I + 3A + 3A² + A³. Using A² = A gives A³ = A·A = A, so the expansion collapses to I + 7A, and subtracting 7A leaves I. Treating A² = A as though it made A itself an identity is what leads to the answer A.
- Q3Easy
If f(x) = (x² − 9)/(x − 3) for x ≠ 3 and f(3) = k, then f is continuous at x = 3 when k equals:
A.3B.6✓ CorrectC.0D.9Answer: B. 6
Explanation: Factorising, (x² − 9)/(x − 3) = x + 3 for every x ≠ 3, so the limit as x → 3 is 6. Continuity requires f(3) to equal that limit, hence k = 6. Substituting x = 3 into the uncancelled fraction gives the indeterminate 0/0 and tempts the answer 0.
- Q4Medium
The value of tan⁻¹(1) + cos⁻¹(−1/2) + sin⁻¹(−1/2) is:
A.13π/12B.5π/12C.3π/4✓ CorrectD.11π/12Answer: C. 3π/4
Explanation: Read each inverse on its own principal branch: tan⁻¹1 = π/4, cos⁻¹(−1/2) = 2π/3 because cos⁻¹ has range [0, π], and sin⁻¹(−1/2) = −π/6 because sin⁻¹ has range [−π/2, π/2]. Adding, 3π/12 + 8π/12 − 2π/12 = 3π/4. Taking sin⁻¹(−1/2) as +π/6 gives 13π/12, and omitting that term altogether gives 11π/12.
- Q5Medium
If A = [[0, −1], [1, 0]], then A²⁰²⁶ equals:
A.IB.AC.−AD.−I✓ CorrectAnswer: D. −I
Explanation: Direct multiplication gives A² = [[−1, 0], [0, −1]] = −I, so A⁴ = (−I)² = I and the powers repeat with period 4. Since 2026 = 4 × 506 + 2, A²⁰²⁶ = A² = −I. Forgetting the minus sign that A² carries leaves the identity.
- Q6Medium
If A is a square matrix of order 3 with |A| = 5, then |adj (2A)| equals:
A.1600✓ CorrectB.200C.100D.25Answer: A. 1600
Explanation: For order 3, |kA| = k³|A| and |adj B| = |B|². Here |2A| = 2³ × 5 = 40, so |adj (2A)| = 40² = 1600. Scaling only once, as |2A| = 2 × 5 = 10, produces 100, and dropping the scalar entirely gives |adj A| = 25.
- Q7Hard
If xʸ = e^(x − y), then dy/dx equals:
A.(x − y)/xB.1/(1 + ln x)C.ln x/(1 + ln x)D.ln x/(1 + ln x)²✓ CorrectAnswer: D. ln x/(1 + ln x)²
Explanation: Taking logarithms gives y ln x = x − y, so y(1 + ln x) = x and y = x/(1 + ln x). Differentiating the log form, y′ ln x + y/x = 1 − y′, so y′ = (x − y)/(x(1 + ln x)); substituting x − y = x ln x/(1 + ln x) gives ln x/(1 + ln x)². Stopping before the second power of (1 + ln x) appears leaves ln x/(1 + ln x).
- Q8Hard
The height of the right circular cylinder of maximum volume that can be inscribed in a sphere of radius 6 cm is:
A.4√3 cm✓ CorrectB.6√2 cmC.12 cmD.2√3 cmAnswer: A. 4√3 cm
Explanation: If the cylinder has height h, its radius satisfies r² = 36 − h²/4, so V = πh(36 − h²/4). Setting dV/dh = π(36 − 3h²/4) = 0 gives h² = 48, so h = 4√3 cm. The value 6√2 solves the different problem of maximising curved surface area, where h = R√2.
Sit the full paper — free
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Attempt this paper free →More Class 12 Mathematics board papers
- Board Paper 1 — you are here
- Board Paper 2 — 20 questions
- Board Paper 3 — 20 questions
- Board Paper 4 — 20 questions
- Board Paper 5 — 20 questions
Prefer chapter-by-chapter revision first? Class 12 Mathematics notes & chapter MCQs →
Questions students ask about this paper
Is this an official CBSE sample paper?
No, and that is on purpose. This is an original paper written by our subject team in the CBSE board pattern. It is not a copy of CBSE's official Sample Question Paper. So you get fresh questions you have not already seen on a dozen other sites, with instant scoring and worked solutions instead of a PDF.
How is this Class 12 Mathematics paper marked?
+1 for a correct answer and 0 for a wrong one — no negative marking, exactly like the real board paper. So attempt every question. A board paper takes nothing away for a wrong answer, and leaving a question blank can only cost you.
How long should this paper take?
30 minutes for 20 questions, about 90 seconds each. The timer keeps running whether you watch it or not, and that is the point. Students lose board marks to poor timing at least as often as to gaps in what they know.
Do I need to pay to attempt it?
No. Sign in free with Google and the full paper opens with a live timer, automatic scoring and a worked solution for every question, including the ones not shown on this page.
