CBSE Class 10 Mathematics Board Paper Set 2 — MCQs with Answers
Original paper · CBSE patternWritten by our subject team, not a reprint of an official sample paper.
- Questions
- 20
- Time
- 25 min
- Marking
- +1, no negative marking
- Mix
- 8 Easy · 8 Medium · 4 Hard
Board Paper Set 2 — CBSE Class 10 Mathematics is a full 20-question objective paper for Class 10 Mathematics, written in the CBSE board pattern and marked the way the board marks: +1 for a correct answer and 0 for a wrong one — no negative marking, exactly like the real board paper. It follows Section A of a real CBSE paper. Q1–Q16 are MCQs with one correct answer. Q17–Q18 are case-based questions on a short source. Q19–Q20 are assertion–reason questions that use the board's own four answer options.
The difficulty mix is 8 Easy · 8 Medium · 4 Hard, balanced the way the board balances Section A. You get 25 minutes, about 75 seconds a question, which is the speed the real paper needs. 8 of the questions are solved in full below, each with the correct option and a worked explanation. Sign in free to attempt the other 12, timed and scored.
From 2026-27, CBSE Class 10 has two board exams a year. The first, around 15 February – 10 March 2027, is compulsory. An optional improvement exam in May 2027 lets you take up to three subjects again, and the better score counts. So you get two real attempts, and timed practice between February and May matters far more than it used to.
8 solved questions from this paper
Answer and worked explanation shown for each. The remaining 12 are timed and scored when you sign in free.
- Q1Easy
The pair of equations x + 2y = 5 and 3x + 6y = 15 has:
A.exactly one solutionB.no solutionC.exactly two solutionsD.infinitely many solutions✓ CorrectAnswer: D. infinitely many solutions
Explanation: Comparing the ratios, 1/3 = 2/6 = 5/15, so all three ratios are equal and the two equations represent the same line. Coincident lines overlap at every point, which means infinitely many common solutions rather than a single point of intersection.
- Q2Easy
The sum of two numbers is 27 and their difference is 5. The larger of the two numbers is:
A.11B.22C.16✓ CorrectD.13.5Answer: C. 16
Explanation: Let the numbers be x and y with x + y = 27 and x − y = 5. Adding the two equations gives 2x = 32, so x = 16 and then y = 11. Halving only the sum gives 13.5, which ignores the difference altogether.
- Q3Easy
The 11th term of the AP −3, −1/2, 2, 9/2, … is:
A.25B.19.5C.−22D.22✓ CorrectAnswer: D. 22
Explanation: The common difference is −1/2 − (−3) = 5/2. Using aₙ = a + (n − 1)d, a₁₁ = −3 + 10 × 5/2 = −3 + 25 = 22. Adding only the ten common differences and forgetting the first term gives 25.
- Q4Medium
Which of the following rational numbers has a terminating decimal expansion?
A.17/8✓ CorrectB.5/6C.7/15D.11/21Answer: A. 17/8
Explanation: A rational number in its lowest form terminates only when its denominator is of the form 2ᵐ × 5ⁿ. Here 8 = 2³, so 17/8 terminates. The denominators 6 = 2 × 3, 15 = 3 × 5 and 21 = 3 × 7 each carry a prime other than 2 or 5, so those expansions are non-terminating and repeating.
- Q5Medium
If α and β are the zeroes of the polynomial x² − 6x + 8, then the value of 1/α + 1/β is:
A.4/3B.3/4✓ CorrectC.−3/4D.2/3Answer: B. 3/4
Explanation: For x² − 6x + 8 the sum of the zeroes is 6 and the product is 8. Since 1/α + 1/β = (α + β)/(αβ), the value is 6/8 = 3/4. Writing the expression as (αβ)/(α + β) by mistake turns the answer upside down to 4/3.
- Q6Medium
The quadratic equation kx² − 6x + 1 = 0 has two equal roots when k equals:
A.6B.9✓ CorrectC.4D.36Answer: B. 9
Explanation: Equal roots require the discriminant to be zero: b² − 4ac = 0. Here (−6)² − 4 × k × 1 = 36 − 4k = 0, so k = 9. Setting 36 − 4k equal to the coefficient 6 rather than to zero is what produces the answer 6.
- Q7Hard
The point on the x-axis which is equidistant from the points (2, −5) and (−2, 9) is:
A.(−7, 0)✓ CorrectB.(7, 0)C.(0, −7)D.(−3, 0)Answer: A. (−7, 0)
Explanation: Any point on the x-axis has the form (x, 0). Equating the squared distances gives (x − 2)² + 25 = (x + 2)² + 81, which simplifies to −4x + 29 = 4x + 85, so 8x = −56 and x = −7. The required point is therefore (−7, 0); the point (0, −7) lies on the y-axis, not the x-axis.
- Q8Hard
If 3 cot θ = 4, then the value of (5 sin θ − 3 cos θ)/(5 sin θ + 3 cos θ) is:
A.9B.1/9✓ CorrectC.1/3D.3/5Answer: B. 1/9
Explanation: From 3 cot θ = 4 we get cot θ = 4/3, so tan θ = 3/4 and the right triangle gives sin θ = 3/5 and cos θ = 4/5. Substituting, the expression becomes (3 − 12/5) ÷ (3 + 12/5) = (3/5) ÷ (27/5) = 1/9. Reading cot θ as 3/4 instead of 4/3 turns the value upside down to 9.
Sit the full paper — free
All 20 questions on a 25-minute timer, scored automatically, with a worked solution for every one — including the 12 not shown above. Sign in with Google — no card needed.
Attempt this paper free →More Class 10 Mathematics board papers
- Board Paper — 31 questions
- Board Paper Set 1 — 20 questions
- Board Paper Set 2 — you are here
- Board Paper Set 3 — 20 questions
Prefer chapter-by-chapter revision first? Class 10 Mathematics notes & chapter MCQs →
Questions students ask about this paper
Is this an official CBSE sample paper?
No, and that is on purpose. This is an original paper written by our subject team in the CBSE board pattern. It is not a copy of CBSE's official Sample Question Paper. So you get fresh questions you have not already seen on a dozen other sites, with instant scoring and worked solutions instead of a PDF.
How is this Class 10 Mathematics paper marked?
+1 for a correct answer and 0 for a wrong one — no negative marking, exactly like the real board paper. So attempt every question. A board paper takes nothing away for a wrong answer, and leaving a question blank can only cost you.
How long should this paper take?
25 minutes for 20 questions, about 75 seconds each. The timer keeps running whether you watch it or not, and that is the point. Students lose board marks to poor timing at least as often as to gaps in what they know.
Do I need to pay to attempt it?
No. Sign in free with Google and the full paper opens with a live timer, automatic scoring and a worked solution for every question, including the ones not shown on this page.
Does the May 2027 improvement exam change how I should practise?
It makes timed practice more useful. The better of your two scores counts, so a February attempt that goes badly is no longer final. But that only helps if you know exactly which topics cost you marks. A scored full-length paper tells you that. Re-reading the chapter does not.
