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Class 11 Physics — Chapter 302: Sound

40 practice questions · 20 Easy · 20 Medium

Practise the most important Class 11 Physics questions from Chapter 302, "Sound" — 40 NCERT-aligned multiple-choice questions with answers and explanations. The set is split into 20 Easy and 20 Medium, so you can warm up on the fundamentals and then push into the exam-level problems that separate top scorers in CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

"Sound" is one of the chapters where numerical problem-solving, derivations and conceptual application really pays off. Each MCQ on this chapter is timed and uses exam-grade marking (+4 correct, −1 wrong, 0 skipped), training the same negative-marking accuracy-under-pressure that real papers demand. Every question carries a short explanation, so a wrong answer becomes a quick lesson rather than a dead end — the fastest way to close gaps before a test.

Use this chapter as targeted revision: attempt the Easy set first to confirm your basics on Sound, then move to Medium to test application and problem-solving. Your accuracy, streaks and XP save automatically, and the chapter feeds into your overall Class 11 Physics mastery score. A few sample questions are shown below; sign in free to practise all 40.

Key concepts: Sound (Class 11 Physics)

Sound is a longitudinal wave — a train of compressions and rarefactions that needs a material medium to travel. This chapter studies how fast it moves and why. Newton's formula v = √(P/ρ) treated the process as isothermal and gave too low a value; Laplace corrected it by taking the changes to be adiabatic, giving v = √(γP/ρ), which agrees with experiment. The speed is raised by higher temperature (v ∝ √T) and by humidity, and lowered in a denser gas, while pressure alone has no effect. Reflection of sound gives echoes, reverberation and the sonar method of measuring distance. Using the principle of superposition, two waves of nearly equal frequency produce beats of frequency |f₁ − f₂|. Standing waves fix the notes of a stretched string (the sonometer and its laws) and of air columns in open and closed organ pipes, studied experimentally with the resonance tube. Finally the Doppler effect explains why the pitch of a moving source rises as it approaches and falls as it recedes.

Sound as a longitudinal wave
Sound propagates as a mechanical longitudinal wave in which particles of the medium oscillate back and forth along the direction of travel, creating alternate regions of compression (high pressure) and rarefaction (low pressure). It cannot travel through a vacuum.
Newton's formula and Laplace's correction
Newton assumed sound travels isothermally, giving v = √(P/ρ) ≈ 280 m/s, about 15% too low. Laplace argued the rapid compressions and rarefactions are adiabatic, so the bulk modulus is γP, giving v = √(γP/ρ) ≈ 332 m/s, which matches measurement.
Factors affecting the speed of sound
In a gas the speed rises with absolute temperature as v ∝ √T (about 0.61 m/s per °C in air) and increases with humidity because moist air is less dense. It is smaller in a denser gas (v ∝ 1/√ρ), while a change of pressure at constant temperature has no effect.
Echo
An echo is the distinct repetition of a sound heard after it reflects from a distant rigid surface. Because the ear separates two sounds only if they are at least about 0.1 s apart, the reflector must be at least roughly 17 m away (at 340 m/s).
Reverberation
Reverberation is the persistence of sound in a closed hall caused by repeated reflections from the walls, ceiling and floor after the source has stopped. Too much of it blurs speech, so auditoriums use soft, absorbing materials to shorten the reverberation time.
Principle of superposition
When two or more waves overlap, the resultant displacement at each point is the vector (algebraic) sum of the individual displacements. This single principle underlies interference, beats and the formation of standing waves in strings and air columns.
Beats
Beats are the periodic rise and fall in loudness heard when two notes of slightly different frequencies superpose. The beat frequency equals the difference of the two frequencies, |f₁ − f₂|; beats are used to tune musical instruments and to find an unknown frequency.
Vibrations of a stretched string
A string fixed at both ends supports standing waves whose fundamental is f = (1/2L)√(T/μ), and it can sound all harmonics f, 2f, 3f… The laws of vibrating strings state f ∝ 1/L, f ∝ √T and f ∝ 1/√μ, and are verified using a sonometer.
Vibrations of air columns
A pipe closed at one end has fundamental f = v/4L and sounds only odd harmonics (f, 3f, 5f…), while a pipe open at both ends has f = v/2L and sounds all harmonics. A small end correction (about 0.3 × diameter per open end) makes the effective length slightly longer.
Resonance and the resonance tube
Resonance occurs when an air column is driven at its natural frequency and vibrates with large amplitude. In the resonance-tube experiment a closed column resonates with a fork when its length equals λ/4, 3λ/4…; the two lengths give λ = 2(L₂ − L₁) and hence the speed of sound.
Doppler effect for sound
The Doppler effect is the apparent change of frequency due to relative motion between source and observer. Approach raises the pitch and recession lowers it, described by f' = f(v ± v_o)/(v ∓ v_s), where the signs are chosen so that approach increases f'.

Key formulas — Sound

Speed of a wave
v = f λ
Newton–Laplace speed of sound
v = √(γP/ρ)
Speed of sound vs temperature
v_t ≈ v_0 + 0.61 t
Echo / sonar distance
d = v t / 2
Beat frequency
n = |f₁ − f₂|
String fundamental frequency
f = (1/2L)√(T/μ)
Closed pipe fundamental
f = v / 4L
Open pipe fundamental
f = v / 2L
Doppler apparent frequency
f' = f(v ± v_o)/(v ∓ v_s)

💡 Exam tips for Sound

  • Remember Newton assumed isothermal and got ~280 m/s; Laplace assumed adiabatic (bulk modulus = γP) and fixed it to ~332 m/s — the extra factor is √γ.
  • For echo, sonar and any 'to-and-fro' reflection problem, the sound covers twice the distance, so always divide (v × t) by 2.
  • Closed pipes give only odd harmonics (f, 3f, 5f…) with fundamental v/4L; open pipes give all harmonics with fundamental v/2L — an open pipe of the same length is one octave higher.
  • In the Doppler formula f' = f(v ± v_o)/(v ∓ v_s), pick signs so that any approach raises f' and any recession lowers it; if source and observer have the same velocity there is no shift.
  • Beats need a small frequency difference; to identify an unknown fork, load one with wax (which lowers its frequency) and see whether the beat count rises or falls.

Sample questions with answers & solutions

Q1Easy

While deriving his formula for the speed of sound in a gas, Newton assumed that the compressions and rarefactions take place

A.so rapidly that no heat is exchanged with the surroundings
B.only at very high pressures
C.so slowly that the temperature of the gas remains constant✓ correct
D.at constant volume
Why

Newton assumed the process is isothermal (temperature constant), so the bulk modulus equals the pressure P, giving v = √(P/ρ).

Q2Medium

The speed of sound in air at 0 °C is 332 m/s and it rises by about 0.61 m/s for every 1 °C rise in temperature. The approximate speed of sound at 25 °C is

A.332 m/s
B.347 m/s✓ correct
C.320 m/s
D.357 m/s
Why

v = 332 + 0.61 × 25 = 332 + 15.25 ≈ 347 m/s.

Q3Easy

Laplace corrected Newton's formula by treating the propagation of sound in a gas as an adiabatic process. His expression for the speed of sound is

A.v = √(γP/ρ)✓ correct
B.v = √(P/ρ)
C.v = √(ρ/P)
D.v = √(P/γρ)
Why

For an adiabatic change the bulk modulus is γP, so v = √(γP/ρ); the extra factor √γ raises the predicted speed to match experiment.

Q4Medium

The speed of sound in air at 0 °C (273 K) is 330 m/s. Assuming the speed is proportional to the square root of the absolute temperature, its speed at 100 °C (373 K) is about

A.330 m/s
B.300 m/s
C.450 m/s
D.386 m/s✓ correct
Why

v₂ = v₁√(T₂/T₁) = 330 × √(373/273) ≈ 330 × 1.169 ≈ 386 m/s.

Q5Easy

As the temperature of the air rises, the speed of sound in it

A.decreases because the air becomes less dense
B.remains exactly the same
C.first increases and then decreases
D.increases, since speed is proportional to the square root of the absolute temperature✓ correct
Why

Since v ∝ √T (T in kelvin), heating the air increases the speed of sound by about 0.61 m/s for each 1 °C rise.

Q6Medium

Newton's (isothermal) formula gives the speed of sound in air as about 280 m/s. Applying Laplace's correction with γ = 1.4, the corrected speed is about

A.331 m/s✓ correct
B.280 m/s
C.235 m/s
D.392 m/s
Why

Laplace's value = Newton's value × √γ = 280 × √1.4 ≈ 280 × 1.183 ≈ 331 m/s, close to the measured value.

Sound — FAQs

What are the key concepts in Class 11 Physics Sound?+

Sound is a longitudinal wave — a train of compressions and rarefactions that needs a material medium to travel. This chapter studies how fast it moves and why. Newton's formula v = √(P/ρ) treated the process as isothermal and gave too low a value; Laplace corrected it by taking the changes to be adiabatic, giving v = √(γP/ρ), which agrees with experiment. The speed is raised by higher temperature (v ∝ √T) and by humidity, and lowered in a denser gas, while pressure alone has no effect. Reflection of sound gives echoes, reverberation and the sonar method of measuring distance. Using the principle of superposition, two waves of nearly equal frequency produce beats of frequency |f₁ − f₂|. Standing waves fix the notes of a stretched string (the sonometer and its laws) and of air columns in open and closed organ pipes, studied experimentally with the resonance tube. Finally the Doppler effect explains why the pitch of a moving source rises as it approaches and falls as it recedes. Key ideas include Sound as a longitudinal wave, Newton's formula and Laplace's correction, Factors affecting the speed of sound, Echo, Reverberation.

What does Class 11 Physics Chapter 302 (Sound) cover on XamBaaz?+

It covers 40 NCERT-aligned MCQs on "Sound" — 20 Easy and 20 Medium — each with a timed quiz and an instant explanation, suitable for CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

Are these "Sound" questions free to practise?+

Yes — sign in with Google to practise "Sound" free. Full unlimited access is ₹999/year (limited-time launch price), with no per-chapter charges.

How should I revise "Sound" for the exam?+

Start with the Easy quiz to confirm your fundamentals, then attempt Medium for application-level practice. Review each explanation, retry the questions you miss, and track your accuracy on this chapter until it is consistently high.

Are these "Sound" MCQs available with answers?+

Yes. The sample questions on this page show the correct option and a "Why" explanation right away — no sign-in needed to read them. Sign in free to attempt all 40 questions with instant scoring.

Is there negative marking in the "Sound" quizzes?+

Yes — the timed quizzes use exam-grade marking: +4 for a correct answer, −1 for a wrong one and 0 for a skipped question, so you practise the same negative-marking discipline as CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

Are these important questions for Sound?+

The set is curated to the NCERT syllabus and weighted toward the question patterns that actually appear in CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG, across Easy and Medium — so it doubles as an "important questions" revision list for "Sound".

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