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Amines — Class 12 MCQs with Answers

Class 12 CBSE Chemistry · Chapter 9

96 practice questions · 32 Easy · 32 Medium · 32 Hard · Updated

Practise the most important Class 12 CBSE Chemistry questions from Chapter 9, "Amines". You get 9 timed quizzes made from 96 NCERT-based MCQs, with answers and explanations. The questions are split into 32 Easy, 32 Medium and 32 Hard. Warm up on the basics, then move on to the exam-level questions that set top scorers in CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG apart.

To score well in "Amines", focus on reactions, key concepts and careful numericals. Each MCQ here is timed and uses exam-style marking (+4 correct, −1 wrong, 0 skipped). This trains you to stay accurate under time pressure, as real papers need. Every question has a short explanation, so a wrong answer becomes a quick lesson. It is the fastest way to fix gaps before a test.

Use this chapter for focused revision. Start with the Easy set to check your basics on Amines, then move to Medium and Hard to practise applying them. Your accuracy, streaks and XP save automatically. This chapter also adds to your overall Class 12 Chemistry mastery score. 14 sample questions are solved in full below, with the answer and a worked explanation. Sign in free to start practising.

Key concepts: Amines (Class 12 Chemistry)

Amines covers the classification, preparation, basicity and reactions of ammonia derivatives, and the rich chemistry of aromatic diazonium salts. Named reactions run through it: Hofmann bromamide degradation and the Gabriel synthesis (for 1° amines), the carbylamine test, diazotisation, and the Sandmeyer and coupling reactions.

Classification
Amines are ammonia derivatives — primary (RNH₂), secondary (R₂NH) and tertiary (R₃N) by the number of alkyl/aryl groups on nitrogen; aniline is the key aromatic amine.
Preparation of amines
By reduction of nitro compounds and nitriles, ammonolysis of haloalkanes (gives a mixture), and the Gabriel and Hofmann routes that yield pure 1° amines.
Basic nature of amines
The lone pair on nitrogen accepts a proton, so amines are basic; alkyl (+I) groups increase basicity and stabilise the ammonium ion formed.
Basicity order in water
Not simply 3° > 2° > 1°: solvation of the cation and steric crowding compete with the +I effect, so for methylamines it is often 2° > 1° > 3° in water.
8 more key concepts, 7 formulas, exam tips free with sign-in.

Amines — important questions & MCQs with answers (Class 12 Chemistry)

14 solved questions from this chapter's difficulty levels, each with its answer and explanation. The other 82 are timed and scored when you sign in.

  1. Q1Easy

    Functional group of amines:

    A.−OH
    B.−CHO
    C.−NH₂ / −NHR / −NR₂✓ Correct
    D.−COOH

    Answer: C. −NH₂ / −NHR / −NR₂

    Explanation: Amines carry −NH₂, −NHR or −NR₂ (1°, 2°, 3° by substituents on N) — the lone pair on N, not −OH, −CHO or −COOH, is what makes the group basic and nucleophilic.

  2. Q2Easy

    The carbylamine test is used to detect:

    A.Primary amines only✓ Correct
    B.Secondary amines
    C.Tertiary amines
    D.Quaternary salts

    Answer: A. Primary amines only

    Explanation: Only primary amines (aliphatic or aromatic) react with CHCl₃ and alc. KOH to give foul-smelling isocyanides (carbylamines).

  3. Q3Easy

    Amines are:

    A.Salts only
    B.Acids
    C.Neutral always
    D.Lewis/Brønsted bases (lone pair on N)✓ Correct

    Answer: D. Lewis/Brønsted bases (lone pair on N)

    Explanation: The lone pair on N accepts H⁺, so amines act as Brønsted bases, and donates it to electrophiles, so they are also Lewis bases — never call them acidic or inert.

  4. Q4Easy

    Aniline reacts with NaNO₂/HCl at 273-278 K to give:

    A.Nitrobenzene
    B.Phenol
    C.Benzenediazonium chloride✓ Correct
    D.Chlorobenzene

    Answer: C. Benzenediazonium chloride

    Explanation: At 0-5 °C aniline undergoes diazotisation with HNO₂ (NaNO₂ + HCl) to give benzenediazonium chloride, C₆H₅N₂⁺Cl⁻.

  5. Q5Easy

    Which of the following is a primary (1°) amine?

    A.CH₃NH₂✓ Correct
    B.(CH₃)₂NH
    C.(CH₃)₃N
    D.C₆H₅N(CH₃)₂

    Answer: A. CH₃NH₂

    Explanation: 1°, 2°, 3° amine classification counts alkyl/aryl groups bonded to N, not H atoms: CH₃NH₂ has just one such group, so it is primary, unlike (CH₃)₂NH, (CH₃)₃N or the N,N-disubstituted aniline in the other options.

  6. Q6Easy

    Aniline on reaction with acetic anhydride gives:

    A.Benzamide
    B.Anilinium acetate
    C.Nitrobenzene
    D.Acetanilide✓ Correct

    Answer: D. Acetanilide

    Explanation: The lone pair on aniline's -NH₂ attacks the carbonyl carbon of (CH₃CO)₂O, acylating N to give acetanilide, C₆H₅NHCOCH₃ — a neutral amide, unlike the salt formed with a plain acid.

  7. Q7Medium

    In aqueous phase, basicity order of methylamines is generally:

    A.1° > 2° > 3°
    B.3° > 2° > 1°
    C.2° > 1° > 3° (in water)✓ Correct
    D.All same

    Answer: C. 2° > 1° > 3° (in water)

    Explanation: In water, solvation of the ammonium ion and steric hindrance override the inductive effect, giving (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N — the reverse of the gas-phase 3° > 2° > 1° order students often assume holds in solution.

  8. Q8Medium

    Hofmann bromamide reaction converts:

    A.Primary amide → primary amine (one C less)✓ Correct
    B.Amine → amide
    C.Acid → ester
    D.Alcohol → ether

    Answer: A. Primary amide → primary amine (one C less)

    Explanation: Hofmann bromamide degradation: RCONH₂ + Br₂ + 4NaOH → RNH₂ + Na₂CO₃ + 2NaBr + 2H₂O via an isocyanate intermediate, shrinking the chain by one carbon — the product is the amine, not an amide or ester.

  9. Q9Medium

    In the gas phase, the correct order of basicity of methylamines is:

    A.NH₃ > CH₃NH₂ > (CH₃)₂NH > (CH₃)₃N
    B.(CH₃)₃N > (CH₃)₂NH > CH₃NH₂ > NH₃✓ Correct
    C.(CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃
    D.CH₃NH₂ > (CH₃)₂NH > (CH₃)₃N > NH₃

    Answer: B. (CH₃)₃N > (CH₃)₂NH > CH₃NH₂ > NH₃

    Explanation: In the gas phase only +I effect matters (no solvation), so basicity rises with the number of methyl groups: 3° > 2° > 1° > NH₃.

  10. Q10Medium

    In the Hinsberg test, a tertiary amine:

    A.Gives a precipitate soluble in KOH
    B.Does not react with C₆H₅SO₂Cl✓ Correct
    C.Gives a precipitate insoluble in KOH
    D.Gives carbylamine

    Answer: B. Does not react with C₆H₅SO₂Cl

    Explanation: Tertiary amines lack N-H, so they do not react with benzenesulphonyl chloride and remain unaffected.

  11. Q11Medium

    The correct order of basicity in aqueous solution for methylamines is:

    A.(CH₃)₃N > (CH₃)₂NH > CH₃NH₂ > NH₃
    B.NH₃ > CH₃NH₂ > (CH₃)₂NH > (CH₃)₃N
    C.CH₃NH₂ > (CH₃)₂NH > (CH₃)₃N > NH₃
    D.(CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃✓ Correct

    Answer: D. (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃

    Explanation: In water, +I, steric hindrance and H-bonding stabilisation of the cation together give the order (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃.

  12. Q12Hard

    Aniline is less basic than aliphatic amines because:

    A.No reason
    B.Heavier
    C.More volatile
    D.Lone pair on N is delocalised into benzene ring✓ Correct

    Answer: D. Lone pair on N is delocalised into benzene ring

    Explanation: Aniline's N lone pair delocalises into the ring by resonance with the ortho/para carbons, leaving less electron density to bind H⁺ — so aniline is far weaker a base than aliphatic amines like methylamine.

  13. Q13Hard

    Diazonium salts are:

    A.Stable forever
    B.Useful intermediates for many aromatic substitutions✓ Correct
    C.Inert
    D.Fuels

    Answer: B. Useful intermediates for many aromatic substitutions

    Explanation: Diazonium salts (ArN₂⁺) form only below 5 °C from primary aromatic amines and serve as reactive intermediates for Sandmeyer substitutions, azo coupling and deamination — they are not stable or inert.

  14. Q14Hard

    The pKb values (aqueous) are: methylamine 3.38, dimethylamine 3.27, trimethylamine 4.22 and ammonia 4.75. The anomalous low basicity of (CH₃)₃N is best explained by:

    A.Only +I effect of three methyls
    B.Steric hindrance around N and poor solvation of (CH₃)₃NH⁺ by H₂O via H-bonds✓ Correct
    C.Resonance with methyl groups
    D.sp² hybridisation of N

    Answer: B. Steric hindrance around N and poor solvation of (CH₃)₃NH⁺ by H₂O via H-bonds

    Explanation: Three -CH₃ groups crowd the N and reduce H-bond solvation stabilisation of the conjugate acid, lowering basicity despite the +I effect.

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Amines — FAQs

What are the key concepts in Class 12 Chemistry Amines?+

Amines covers the classification, preparation, basicity and reactions of ammonia derivatives, and the rich chemistry of aromatic diazonium salts. Named reactions run through it: Hofmann bromamide degradation and the Gabriel synthesis (for 1° amines), the carbylamine test, diazotisation, and the Sandmeyer and coupling reactions. Key ideas include Classification, Preparation of amines, Basic nature of amines, Basicity order in water.

What does Class 12 Chemistry Chapter 9 (Amines) cover on XamBaaz?+

It has 96 NCERT-based MCQs on "Amines": 32 Easy, 32 Medium and 32 Hard. Together they make 9 timed quizzes, and you never get the same set twice. Every question has an instant explanation. They help you prepare for CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

Are these "Amines" questions free to practise?+

Yes. Sign in with Google to practise "Amines" free. Full unlimited access is ₹999/year on a launch offer until 1 December 2026. No chapter is charged separately.

How should I revise "Amines" for the exam?+

Start with the Easy quiz to check your basics, then try Medium and Hard to practise applying them. There are 9 timed quizzes on this chapter, so you can come back for a fresh set instead of one you have seen. Read each explanation, retry the questions you miss, and track your accuracy until it stays high.

Are these "Amines" MCQs available with answers?+

Yes. 14 sample questions are shown here in full, each with the correct option and a step-by-step "Why" explanation. Sign in free with Google to start practising, with instant scoring.

Is there negative marking in the "Amines" quizzes?+

Yes. The timed quizzes use exam-style marking: +4 for a right answer, −1 for a wrong one and 0 for a skip, the same negative marking as JEE Main, JEE Advanced and NEET UG. MHT-CET and CBSE board papers have no negative marking. Our mocks for those are scored their way.

What are the important questions from Amines (Class 12 Chemistry)?+

The questions that matter most test Classification, Preparation of amines, Basic nature of amines, Basicity order in water. This page shows 14 solved important MCQs with answers and explanations; all 96 questions on the chapter are available as timed quizzes once you sign in.

Is there an online quiz for Amines?+

Yes — Class 12 Chemistry Amines has timed online quizzes at Easy, Medium and Hard levels, with instant scoring and a worked explanation on every question. The first quiz on the chapter is free.

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