Class 12 Chemistry — Chapter 1: Solutions
98 practice questions · 33 Easy · 33 Medium · 32 Hard
Free NCERT-aligned multiple-choice practice for Class 12 Chemistry, Chapter 1 (Solutions). Practise timed Easy, Medium and Hard quizzes with instant explanations — built for CBSE Board exams, JEE Main and NEET UG. Here are a few sample questions; sign in free to practise all 98.
Sample questions
Molarity is defined as:
Molarity (M) = moles of solute / volume of solution in litres.
What is the molarity of a solution containing 9.8 g of H₂SO₄ in 250 mL of solution? (Molar mass = 98 g/mol)
Moles = 9.8/98 = 0.1. Molarity = 0.1 / 0.250 L = 0.4 M.
Calculate the freezing point depression of a solution containing 1.8 g glucose (M = 180 g/mol) in 100 g water. K_f for water = 1.86 K·kg/mol.
Molality = (1.8/180)/0.100 = 0.1. ΔT_f = 1.86 × 0.1 = 0.186 K.
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