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Chemical Kinetics — Class 12 MCQs with Answers

Class 12 CBSE Chemistry · Chapter 3

96 practice questions · 32 Easy · 32 Medium · 32 Hard · Updated

Practise the most important Class 12 CBSE Chemistry questions from Chapter 3, "Chemical Kinetics". You get 9 timed quizzes made from 96 NCERT-based MCQs, with answers and explanations. The questions are split into 32 Easy, 32 Medium and 32 Hard. Warm up on the basics, then move on to the exam-level questions that set top scorers in CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG apart.

To score well in "Chemical Kinetics", focus on reactions, key concepts and careful numericals. Each MCQ here is timed and uses exam-style marking (+4 correct, −1 wrong, 0 skipped). This trains you to stay accurate under time pressure, as real papers need. Every question has a short explanation, so a wrong answer becomes a quick lesson. It is the fastest way to fix gaps before a test.

Use this chapter for focused revision. Start with the Easy set to check your basics on Chemical Kinetics, then move to Medium and Hard to practise applying them. Your accuracy, streaks and XP save automatically. This chapter also adds to your overall Class 12 Chemistry mastery score. 14 sample questions are solved in full below, with the answer and a worked explanation. Sign in free to start practising.

Key concepts: Chemical Kinetics (Class 12 Chemistry)

Chemical Kinetics studies reaction rates and their control: rate laws and order (found experimentally, not from stoichiometry), molecularity, integrated rate equations for zero and first order, half-life, the Arrhenius temperature dependence with activation energy, collision theory, and how a catalyst speeds a reaction by lowering Ea without shifting equilibrium.

Rate of reaction
Change in concentration of a reactant or product per unit time: −d[R]/dt or +d[P]/dt. Average rate is over an interval; instantaneous rate is at one instant.
Rate law and rate constant
Rate = k[A]^x[B]^y; k is the rate constant, independent of concentration but dependent on temperature and catalyst.
Order of reaction
Sum of the powers of concentration in the rate law (x + y). Determined EXPERIMENTALLY, can be zero, fractional or negative — never read from the equation.
Molecularity vs order
Molecularity is the number of species colliding in an elementary step (a positive whole number ≤ 3); order is experimental and can be zero or fractional.
8 more key concepts, 6 formulas, exam tips free with sign-in.

Chemical Kinetics — important questions & MCQs with answers (Class 12 Chemistry)

14 solved questions from this chapter's difficulty levels, each with its answer and explanation. The other 82 are timed and scored when you sign in.

  1. Q1Easy

    Rate of reaction is:

    A.Change in concentration per unit time✓ Correct
    B.Total mass
    C.Volume change
    D.Temperature change

    Answer: A. Change in concentration per unit time

    Explanation: Rate is −d[R]/dt for a reactant or +d[P]/dt for a product: concentration change per unit time. Total mass and volume don't change during reaction, and temperature is not what rate measures.

  2. Q2Easy

    Units of rate constant for first-order:

    A.unitless
    B.M·s⁻¹
    C.M⁻¹·s⁻¹
    D.s⁻¹✓ Correct

    Answer: D. s⁻¹

    Explanation: Since rate = k[A]¹, units of k = (mol·L⁻¹·s⁻¹)/(mol·L⁻¹) = s⁻¹ — concentration cancels out, leaving inverse time, unlike second-order k which keeps L·mol⁻¹·s⁻¹.

  3. Q3Easy

    The rate of a chemical reaction is best defined as the change in:

    A.pressure of gases per unit area
    B.mass of reactant per unit volume
    C.temperature per unit time
    D.concentration of reactant or product per unit time✓ Correct

    Answer: D. concentration of reactant or product per unit time

    Explanation: Rate of reaction is the change in concentration of any reactant or product divided by the time interval — not pressure per area, mass per volume, or temperature change.

  4. Q4Easy

    Order of a reaction is:

    A.number of reactant molecules in the balanced equation
    B.sum of stoichiometric coefficients of reactants
    C.sum of powers of concentration terms in the rate law✓ Correct
    D.always equal to molecularity

    Answer: C. sum of powers of concentration terms in the rate law

    Explanation: Order of reaction is the sum of the powers of concentration terms in the experimentally determined rate law — not the coefficients in the balanced equation, and it need not equal molecularity.

  5. Q5Easy

    The SI unit of rate of a reaction in solution is:

    A.mol·s⁻¹
    B.L·mol⁻¹·s⁻¹
    C.mol·L⁻¹·s⁻¹✓ Correct
    D.s⁻¹

    Answer: C. mol·L⁻¹·s⁻¹

    Explanation: Rate = Δconcentration/Δtime, so its SI unit is mol·L⁻¹·s⁻¹. L·mol⁻¹·s⁻¹ and s⁻¹ are units of the rate CONSTANT k for particular orders, not of rate itself.

  6. Q6Easy

    Units of the rate constant k for a zero-order reaction are:

    A.mol·L⁻¹·s⁻¹✓ Correct
    B.s⁻¹
    C.L·mol⁻¹·s⁻¹
    D.L²·mol⁻²·s⁻¹

    Answer: A. mol·L⁻¹·s⁻¹

    Explanation: For zero order, rate = k[A]⁰ = k, so k carries exactly the same units as rate itself: mol·L⁻¹·s⁻¹ — there is no concentration term left to change the units.

  7. Q7Medium

    Arrhenius equation: k =

    A.A/Ea
    B.A·e^(Ea/RT)
    C.A·e^(−Ea/RT)✓ Correct
    D.Ea/RT

    Answer: C. A·e^(−Ea/RT)

    Explanation: k = A·e⁻ᴱᵃ/ᴿᵀ has a negative exponent because higher Ea suppresses k — a positive exponent would make k grow with activation energy, backwards from collision theory.

  8. Q8Medium

    Half-life of first-order reaction:

    A.
    B.1/k[A]₀
    C.k·[A]₀
    D.0.693/k (independent of [A]₀)✓ Correct

    Answer: D. 0.693/k (independent of [A]₀)

    Explanation: Integrating −d[A]/dt = k[A] gives t½ = 0.693/k, independent of [A]₀ — the fingerprint separating first order from zero-order (t½ = [A]₀/2k) and second-order (t½ = 1/k[A]₀).

  9. Q9Medium

    In a reaction, [A] falls from 0.50 mol·L⁻¹ to 0.40 mol·L⁻¹ in 10 minutes. The average rate of disappearance of A is:

    A.0.5 × 10⁻² mol·L⁻¹·min⁻¹
    B.1.0 × 10⁻¹ mol·L⁻¹·min⁻¹
    C.1.0 × 10⁻² mol·L⁻¹·min⁻¹✓ Correct
    D.2.0 × 10⁻² mol·L⁻¹·min⁻¹

    Answer: C. 1.0 × 10⁻² mol·L⁻¹·min⁻¹

    Explanation: Average rate = −Δ[A]/Δt = (0.50 − 0.40 mol·L⁻¹)/10 min = 0.010 mol·L⁻¹·min⁻¹ — dividing the concentration drop by the time elapsed, not by the initial or final concentration alone.

  10. Q10Medium

    A first-order reaction is 50% complete in 30 min. The rate constant k (min⁻¹) is approximately:

    A.0.0693
    B.0.0231✓ Correct
    C.0.0100
    D.0.500

    Answer: B. 0.0231

    Explanation: 50% completion is one half-life, so k = 0.693/t½ = 0.693/30 min ≈ 0.0231 min⁻¹ — using 0.693 instead of 1, or forgetting to divide by t½, are the usual slips here.

  11. Q11Medium

    For 2A + B → 3C, if rate of disappearance of A is 0.04 mol·L⁻¹·s⁻¹, the rate of formation of C is:

    A.0.04 mol·L⁻¹·s⁻¹
    B.0.06 mol·L⁻¹·s⁻¹✓ Correct
    C.0.02 mol·L⁻¹·s⁻¹
    D.0.12 mol·L⁻¹·s⁻¹

    Answer: B. 0.06 mol·L⁻¹·s⁻¹

    Explanation: For 2A + B → 3C, rate = −(1/2)d[A]/dt = (1/3)d[C]/dt, so d[C]/dt = (3/2)×0.04 = 0.06 mol·L⁻¹·s⁻¹ — C forms 1.5× as fast as A disappears, from the 3:2 mole ratio.

  12. Q12Hard

    Catalyst:

    A.Increases ΔG
    B.Lowers activation energy without changing equilibrium position✓ Correct
    C.Adds mass to products
    D.Shifts equilibrium

    Answer: B. Lowers activation energy without changing equilibrium position

    Explanation: A catalyst opens a lower-Ea pathway for both forward and reverse reactions equally, so it speeds up both directions and leaves the equilibrium position and ΔG unchanged.

  13. Q13Hard

    For zero-order reaction, rate is:

    A.Independent of concentration✓ Correct
    B.Square of concentration
    C.Inverse
    D.Same as first order

    Answer: A. Independent of concentration

    Explanation: Zero order means rate = k[A]⁰ = k: rate stays constant as [A] falls, right up to the moment reactant runs out — unlike first order, where rate keeps dropping with concentration.

  14. Q14Hard

    A first-order reaction has Ea = 104.6 kJ·mol⁻¹ and t½ = 6.93 h at 300 K. The rate constant at 350 K is approximately (R = 8.314 J·K⁻¹·mol⁻¹):

    A.≈ 5.0 × 10⁻¹ s⁻¹
    B.≈ 2.78 × 10⁻⁵ s⁻¹
    C.≈ 1.1 × 10⁻² s⁻¹✓ Correct
    D.≈ 1.0 × 10⁻⁸ s⁻¹

    Answer: C. ≈ 1.1 × 10⁻² s⁻¹

    Explanation: First get k at 300 K: 0.693/(6.93×3600) = 2.78×10⁻⁵ s⁻¹. Then ln(k₂/k₁) = (104600/8.314)(1/300 − 1/350) ≈ 5.99, a factor of about 400, so k₂ ≈ 1.1×10⁻² s⁻¹. Converting hours to seconds first is essential.

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Chemical Kinetics — FAQs

What are the key concepts in Class 12 Chemistry Chemical Kinetics?+

Chemical Kinetics studies reaction rates and their control: rate laws and order (found experimentally, not from stoichiometry), molecularity, integrated rate equations for zero and first order, half-life, the Arrhenius temperature dependence with activation energy, collision theory, and how a catalyst speeds a reaction by lowering Ea without shifting equilibrium. Key ideas include Rate of reaction, Rate law and rate constant, Order of reaction, Molecularity vs order.

What does Class 12 Chemistry Chapter 3 (Chemical Kinetics) cover on XamBaaz?+

It has 96 NCERT-based MCQs on "Chemical Kinetics": 32 Easy, 32 Medium and 32 Hard. Together they make 9 timed quizzes, and you never get the same set twice. Every question has an instant explanation. They help you prepare for CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

Are these "Chemical Kinetics" questions free to practise?+

Yes. Sign in with Google to practise "Chemical Kinetics" free. Full unlimited access is ₹999/year on a launch offer until 1 December 2026. No chapter is charged separately.

How should I revise "Chemical Kinetics" for the exam?+

Start with the Easy quiz to check your basics, then try Medium and Hard to practise applying them. There are 9 timed quizzes on this chapter, so you can come back for a fresh set instead of one you have seen. Read each explanation, retry the questions you miss, and track your accuracy until it stays high.

Are these "Chemical Kinetics" MCQs available with answers?+

Yes. 14 sample questions are shown here in full, each with the correct option and a step-by-step "Why" explanation. Sign in free with Google to start practising, with instant scoring.

Is there negative marking in the "Chemical Kinetics" quizzes?+

Yes. The timed quizzes use exam-style marking: +4 for a right answer, −1 for a wrong one and 0 for a skip, the same negative marking as JEE Main, JEE Advanced and NEET UG. MHT-CET and CBSE board papers have no negative marking. Our mocks for those are scored their way.

What are the important questions from Chemical Kinetics (Class 12 Chemistry)?+

The questions that matter most test Rate of reaction, Rate law and rate constant, Order of reaction, Molecularity vs order. This page shows 14 solved important MCQs with answers and explanations; all 96 questions on the chapter are available as timed quizzes once you sign in.

Is there an online quiz for Chemical Kinetics?+

Yes — Class 12 Chemistry Chemical Kinetics has timed online quizzes at Easy, Medium and Hard levels, with instant scoring and a worked explanation on every question. The first quiz on the chapter is free.

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