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States of Matter — Class 11 MCQs with Answers

Class 11 CBSE Chemistry · Chapter 305

40 practice questions · 20 Easy · 20 Medium · Updated

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Practise the most important Class 11 CBSE Chemistry questions from Chapter 305, "States of Matter". You get 4 timed quizzes made from 40 NCERT-based MCQs, with answers and explanations. The questions are split into 20 Easy and 20 Medium. Warm up on the basics, then move on to the exam-level questions that top scorers in CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG get right.

To score well in "States of Matter", focus on reactions, key concepts and careful numericals. Each MCQ here is timed and uses exam-style marking (+4 correct, −1 wrong, 0 skipped). This helps you stay accurate when time is short, just as real papers need. Every question has a short explanation, so a wrong answer becomes a quick lesson. It is the fastest way to fix gaps before a test.

Use this chapter for focused revision. Start with the Easy set to check your basics on States of Matter, then move to Medium to practise applying them. Your accuracy, streaks and XP save automatically. This chapter also adds to your overall Class 11 Chemistry mastery score. Try the 4 sample questions below: tap an option to see the answer and a worked explanation. Sign in free to start practising.

States of Matter — important questions & MCQs with answers (Class 11 Chemistry)

4 solved questions from this chapter's difficulty levels, each with its answer and explanation. Tap an option to check yourself.

0 of 4 answered

  1. Q1 of 4Easy

    The weakest intermolecular force, which is present even between the atoms of a noble gas such as argon, is

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    Answer: the London dispersion force

    Explanation: Momentary shifts in the electron cloud create instantaneous dipoles, so London dispersion forces act between all particles, including non-polar atoms like argon.

  2. Q2 of 4Easy

    Boyle's law states that for a fixed mass of gas

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    Answer: V ∝ 1/P at constant temperature

    Explanation: Boyle's law is the pressure-volume law: at constant temperature the volume of a fixed mass of gas varies inversely with pressure, so PV is constant.

  3. Q3 of 4Medium

    In the van der Waals equation (P + an²/V²)(V − nb) = nRT, the constant b corrects for

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    Answer: the finite volume actually occupied by the gas molecules

    Explanation: The term nb is the excluded volume of the molecules themselves and is subtracted from V, while an²/V² is the pressure correction for intermolecular attraction.

  4. Q4 of 4Medium

    A vessel contains 2 mol of N₂ and 3 mol of O₂ and the total pressure is 5 atm. The partial pressure of O₂ is

    Show answer

    Answer: 3 atm

    Explanation: Mole fraction of O₂ = 3/(2 + 3) = 0.6, so its partial pressure = 0.6 × 5 = 3 atm.

States of Matter notes: key concepts (Class 11 Chemistry)

Whether a substance is a gas, a liquid or a solid is decided by a tug of war between the intermolecular forces pulling its particles together and the thermal energy driving them apart. This chapter first surveys those forces — London dispersion, dipole-dipole and hydrogen bonding — and then studies the gaseous state in detail: the laws of Boyle, Charles, Gay-Lussac and Avogadro, which combine into the ideal gas equation PV = nRT, together with Dalton's law of partial pressures and Graham's law of diffusion. The kinetic molecular theory explains why these laws work and introduces the Maxwell distribution of molecular speeds. Finally, real gases are shown to deviate from ideality at high pressure and low temperature, a deviation measured by the compressibility factor and described by the van der Waals equation, which leads on to critical constants, liquefaction and the properties of the liquid state.

London dispersion forces
Momentary fluctuations in the electron cloud of an atom or molecule create an instantaneous dipole that induces a dipole in its neighbour. These forces act between all particles, including non-polar ones such as He and CH₄, and grow stronger as the number of electrons and the size of the molecule increase.
Dipole-dipole interaction
Molecules with a permanent dipole moment, such as HCl or SO₂, line up so that the positive end of one faces the negative end of the next. These attractions are stronger than dispersion forces between molecules of comparable size, so polar substances usually boil higher than non-polar ones.
Hydrogen bonding
A special, unusually strong dipole-dipole attraction that arises when hydrogen is covalently bonded to the small, highly electronegative atoms F, O or N. It explains the abnormally high boiling points of HF, H₂O and NH₃, the high viscosity of glycerol, and the fact that ice is less dense than water.
Five water molecules, each an oxygen atom bonded to two hydrogen atoms. Dashed blue lines are hydrogen bonds: each joins a hydrogen atom of one molecule to an oxygen atom of a neighbouring molecule, attracted by a lone pair on that oxygen. The central molecule forms four hydrogen bonds, two through its own hydrogen atoms and two to its oxygen. This network of hydrogen bonds holds water molecules together, giving water its high boiling point; in ice it fixes them in an open arrangement, so ice is less dense than water.
Boyle's law
At constant temperature, the volume of a fixed mass of gas varies inversely with the pressure, so that PV stays constant. A plot of P against V is a hyperbola while a plot of P against 1/V is a straight line through the origin, which is the usual way of testing the law.
A pressure–volume graph for a fixed mass of gas, pressure P up the vertical axis and volume V along the horizontal axis. Two curves (rectangular hyperbolas) fall steeply at small volume and flatten at large volume: along each one the product PV stays constant. The green curve is for the lower temperature T₁; the amber curve, for the higher temperature T₂, lies farther from the axes.
Charles' law
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature, so V/T is constant. Extrapolating the straight line of V against Celsius temperature for every gas gives a common intercept at −273.15 °C, which defines absolute zero and the kelvin scale.
A volume–temperature graph for a fixed mass of gas at constant pressure, with volume V up the vertical axis and temperature t in degrees Celsius along the horizontal axis. Two straight lines, for two different constant pressures, rise steadily with temperature. Extended backwards (dashed) they both meet the temperature axis at the same point, −273.15 °C, which is 0 K, absolute zero. So V is proportional to the absolute temperature T in kelvin.
Gay-Lussac's law
At constant volume, the pressure of a fixed mass of gas is directly proportional to its absolute temperature, so P/T is constant. This is the law behind pressure cookers, sealed aerosol cans that burst on heating, and the constant-volume gas thermometer.
Avogadro's law and molar volume
Equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules, so V is proportional to n. It follows that one mole of any ideal gas occupies 22.4 L at STP, taken here as 273 K and 1 atm, whatever the identity of the gas.
Ideal gas equation
Combining the three gas laws with Avogadro's law gives PV = nRT, the equation of state of an ideal gas. Since n = mass ÷ molar mass, the same equation rearranges to M = dRT/P, which is the standard route from a measured gas density to a molar mass.
Dalton's law of partial pressures
In a mixture of non-reacting gases each component exerts the pressure it would exert alone, and the total pressure is the sum of these partial pressures. The rule is essential when a gas is collected over water, where the aqueous tension must be subtracted to obtain the pressure of the dry gas.
Graham's law of diffusion
At the same temperature and pressure the rate of diffusion or effusion of a gas is inversely proportional to the square root of its density, and hence of its molar mass. This is why hydrogen diffuses four times as fast as oxygen and why the law can be used to separate gaseous isotopes.
Kinetic molecular theory
Gases are pictured as very large numbers of tiny particles in ceaseless random motion, whose own volume is negligible, between which there are no appreciable attractions, and whose collisions are perfectly elastic. The average kinetic energy of the particles depends only on the absolute temperature.
Maxwell distribution of speeds
At any temperature the molecules do not all move at the same speed; the fraction having each speed follows a skewed bell-shaped curve. Raising the temperature flattens and broadens the curve and shifts its peak to the right, so more molecules move fast, while heavier gases give narrower curves peaking at lower speeds.
The Maxwell distribution of molecular speeds for the same gas at two temperatures, the fraction of molecules having each speed plotted against speed u. Both curves are skewed bells starting at zero. The curve for the higher temperature T₂ is flatter and broader, and its peak (the most probable speed, dashed) lies farther to the right than the peak for T₁, so at T₂ more molecules move fast. The areas under the two curves are equal.
Three molecular speeds
The most probable speed lies at the peak of the Maxwell curve, the average speed is the arithmetic mean, and the root mean square speed is the square root of the mean of the squared speeds. Because the curve is skewed, they always stand in the fixed ratio 1 : 1.128 : 1.224.
The Maxwell distribution of molecular speeds in a gas: the number of molecules with a given speed plotted against speed v. The curve starts at zero, rises to a single peak and then falls away slowly with a long tail at high speeds. Dashed lines mark three speeds: the most probable speed v_mp at the peak, then the mean speed v̄ a little to its right, then the root mean square speed v_rms further right, so v_mp < v̄ < v_rms.
Deviation of real gases
Real gases obey PV = nRT closely only at low pressure and high temperature. At high pressure the molecules occupy a significant fraction of the container and at low temperature the attractions between them can no longer be ignored, so both simplifying assumptions of the kinetic theory break down.
van der Waals equation
Written as (P + an²/V²)(V − nb) = nRT, it repairs the ideal gas equation with two constants: a measures the intermolecular attraction that lowers the observed pressure, and b is the excluded volume of the molecules themselves. Large values of a and b mark a gas that is easily liquefied.
Compressibility factor Z
Defined as Z = PV/nRT, it equals exactly 1 for an ideal gas. Z below 1 at moderate pressure shows that attractive forces make the gas more compressible than ideal, while Z above 1 at high pressure shows that molecular volume and repulsion make it harder to compress.
A graph of compressibility factor Z = PV/nRT against pressure p. An ideal gas gives the horizontal dashed line Z = 1 at every pressure. For hydrogen, Z rises above 1 steadily from the start. For methane and, much more, for carbon dioxide, Z first dips below 1 at moderate pressure, where attractions make the gas easier to compress, and then rises above 1 at high pressure, where the volume of the molecules makes it harder to compress.
Critical constants and liquefaction
The critical temperature Tc is the temperature above which a gas cannot be liquefied by pressure alone; the pressure needed to liquefy it at Tc is the critical pressure Pc and the volume of one mole there is the critical volume Vc. A high Tc, as in NH₃ or SO₂, means strong attractions and easy liquefaction.
Vapour pressure and boiling point
The vapour pressure of a liquid is the pressure exerted by its vapour in equilibrium with the liquid at a given temperature, and it rises steeply with temperature. A liquid boils when its vapour pressure equals the external pressure, which is why water boils below 100 °C at high altitude.
Vapour pressure against temperature for diethyl ether and water. Both curves rise steeply as temperature increases, the ether curve lying well above the water curve. A horizontal dashed line marks the external pressure of 1 atm, 760 mm Hg. Each liquid boils where its curve meets this line: diethyl ether at 34.6 °C and water at 100 °C, its normal boiling point. At a lower external pressure the line would be lower and the liquid would boil at a lower temperature.
Surface tension
Molecules at the surface of a liquid experience an unbalanced inward pull, so the liquid behaves as if covered by a stretched skin and tries to minimise its surface area. This explains spherical droplets, capillary rise and the cleaning action of detergents, and its value falls as temperature rises.
Viscosity
Viscosity is the internal resistance to flow, caused by friction between adjacent layers of a liquid moving at different speeds. Stronger intermolecular forces mean higher viscosity, so glycerol with its three hydroxyl groups is far more viscous than water, and heating always makes a liquid flow more freely.
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States of Matter — FAQs

What are the key concepts in Class 11 Chemistry States of Matter?+

Whether a substance is a gas, a liquid or a solid is decided by a tug of war between the intermolecular forces pulling its particles together and the thermal energy driving them apart. This chapter first surveys those forces — London dispersion, dipole-dipole and hydrogen bonding — and then studies the gaseous state in detail: the laws of Boyle, Charles, Gay-Lussac and Avogadro, which combine into the ideal gas equation PV = nRT, together with Dalton's law of partial pressures and Graham's law of diffusion. The kinetic molecular theory explains why these laws work and introduces the Maxwell distribution of molecular speeds. Finally, real gases are shown to deviate from ideality at high pressure and low temperature, a deviation measured by the compressibility factor and described by the van der Waals equation, which leads on to critical constants, liquefaction and the properties of the liquid state. Key ideas include London dispersion forces, Dipole-dipole interaction, Hydrogen bonding, Boyle's law, Charles' law, Gay-Lussac's law.

What does Class 11 Chemistry Chapter 305 (States of Matter) cover on XamBaaz?+

It has 40 NCERT-based MCQs on "States of Matter": 20 Easy and 20 Medium. Together they make 4 timed quizzes, and you never get the same set twice. Every question has an instant explanation. They help you prepare for CBSE & Maharashtra HSC Board exams, JEE Main, MHT-CET, JEE Advanced and NEET UG.

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Yes. Sign in with Google to practise "States of Matter" free. Full unlimited access is ₹1,999/year. One year from the day you pay. You stay in Class 11 till 31 March; on 1 April your account moves up to Class 12 and the rest of your year carries over. No chapter is charged separately.

How should I revise "States of Matter" for the exam?+

Start with the Easy quiz to check your basics, then try Medium to practise applying them. There are 4 timed quizzes on this chapter, so you can come back for a fresh set instead of one you have seen. Read each explanation, retry the questions you miss, and track your accuracy until it stays high.

Are these "States of Matter" MCQs available with answers?+

Yes. 4 sample questions are on this page with answers: tap an option, or "Show answer", to see the correct option and a step-by-step explanation. Sign in free with Google to start practising, with instant scoring.

Is there negative marking in the "States of Matter" quizzes?+

Yes. The timed quizzes use exam-style marking: +4 for a right answer, −1 for a wrong one and 0 for a skip, the same negative marking as JEE Main, JEE Advanced and NEET UG. MHT-CET and CBSE board papers have no negative marking. Our mocks for those are scored their way.

What are the important questions from States of Matter (Class 11 Chemistry)?+

The questions that matter most test London dispersion forces, Dipole-dipole interaction, Hydrogen bonding, Boyle's law, Charles' law, Gay-Lussac's law. This page shows 4 solved important MCQs with answers and explanations. Sign in to practise all 40 questions on the chapter as timed quizzes.

Is there an online quiz for States of Matter?+

Yes — Class 11 Chemistry States of Matter has timed online quizzes at Easy and Medium levels, with instant scoring and a worked explanation on every question. The first quiz on the chapter is free.

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Yes. This page has 4 solved questions on States of Matter, each with the correct answer and a short explanation. Sign in to practise all 40 questions on the chapter as timed quizzes.

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