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Class 11 Chemistry — Chapter 305: States of Matter

40 practice questions · 20 Easy · 20 Medium · 0 Hard

Practise the most important Class 11 Chemistry questions from Chapter 305, "States of Matter" — 40 NCERT-aligned multiple-choice questions with answers and explanations. The set is split into 20 Easy, 20 Medium and 0 Hard questions, so you can warm up on the fundamentals and then push into the exam-level problems that separate top scorers in CBSE Board exams, JEE Main, JEE Advanced and NEET UG.

"States of Matter" is one of the chapters where reactions, named concepts, and balanced numerical work really pays off. Each MCQ on this chapter is timed and uses exam-grade marking (+4 correct, −1 wrong, 0 skipped), training the same negative-marking accuracy-under-pressure that real papers demand. Every question carries a short explanation, so a wrong answer becomes a quick lesson rather than a dead end — the fastest way to close gaps before a test.

Use this chapter as targeted revision: attempt the Easy set first to confirm your basics on States of Matter, then move to Medium and Hard to test application and problem-solving. Your accuracy, streaks and XP save automatically, and the chapter feeds into your overall Class 11 Chemistry mastery score. A few sample questions are shown below; sign in free to practise all 40.

Key concepts: States of Matter (Class 11 Chemistry)

Whether a substance is a gas, a liquid or a solid is decided by a tug of war between the intermolecular forces pulling its particles together and the thermal energy driving them apart. This chapter first surveys those forces — London dispersion, dipole-dipole and hydrogen bonding — and then studies the gaseous state in detail: the laws of Boyle, Charles, Gay-Lussac and Avogadro, which combine into the ideal gas equation PV = nRT, together with Dalton's law of partial pressures and Graham's law of diffusion. The kinetic molecular theory explains why these laws work and introduces the Maxwell distribution of molecular speeds. Finally, real gases are shown to deviate from ideality at high pressure and low temperature, a deviation measured by the compressibility factor and described by the van der Waals equation, which leads on to critical constants, liquefaction and the properties of the liquid state.

London dispersion forces
Momentary fluctuations in the electron cloud of an atom or molecule create an instantaneous dipole that induces a dipole in its neighbour. These forces act between all particles, including non-polar ones such as He and CH₄, and grow stronger as the number of electrons and the size of the molecule increase.
Dipole-dipole interaction
Molecules with a permanent dipole moment, such as HCl or SO₂, line up so that the positive end of one faces the negative end of the next. These attractions are stronger than dispersion forces between molecules of comparable size, so polar substances usually boil higher than non-polar ones.
Hydrogen bonding
A special, unusually strong dipole-dipole attraction that arises when hydrogen is covalently bonded to the small, highly electronegative atoms F, O or N. It explains the abnormally high boiling points of HF, H₂O and NH₃, the high viscosity of glycerol, and the fact that ice is less dense than water.
Boyle's law
At constant temperature, the volume of a fixed mass of gas varies inversely with the pressure, so that PV stays constant. A plot of P against V is a hyperbola while a plot of P against 1/V is a straight line through the origin, which is the usual way of testing the law.
Charles' law
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature, so V/T is constant. Extrapolating the straight line of V against Celsius temperature for every gas gives a common intercept at −273.15 °C, which defines absolute zero and the kelvin scale.
Gay-Lussac's law
At constant volume, the pressure of a fixed mass of gas is directly proportional to its absolute temperature, so P/T is constant. This is the law behind pressure cookers, sealed aerosol cans that burst on heating, and the constant-volume gas thermometer.
Avogadro's law and molar volume
Equal volumes of all gases at the same temperature and pressure contain equal numbers of molecules, so V is proportional to n. It follows that one mole of any ideal gas occupies 22.4 L at STP, taken here as 273 K and 1 atm, whatever the identity of the gas.
Ideal gas equation
Combining the three gas laws with Avogadro's law gives PV = nRT, the equation of state of an ideal gas. Since n = mass ÷ molar mass, the same equation rearranges to M = dRT/P, which is the standard route from a measured gas density to a molar mass.
Dalton's law of partial pressures
In a mixture of non-reacting gases each component exerts the pressure it would exert alone, and the total pressure is the sum of these partial pressures. The rule is essential when a gas is collected over water, where the aqueous tension must be subtracted to obtain the pressure of the dry gas.
Graham's law of diffusion
At the same temperature and pressure the rate of diffusion or effusion of a gas is inversely proportional to the square root of its density, and hence of its molar mass. This is why hydrogen diffuses four times as fast as oxygen and why the law can be used to separate gaseous isotopes.
Kinetic molecular theory
Gases are pictured as very large numbers of tiny particles in ceaseless random motion, whose own volume is negligible, between which there are no appreciable attractions, and whose collisions are perfectly elastic. The average kinetic energy of the particles depends only on the absolute temperature.
Maxwell distribution of speeds
At any temperature the molecules do not all move at the same speed; the fraction having each speed follows a skewed bell-shaped curve. Raising the temperature flattens and broadens the curve and shifts its peak to the right, so more molecules move fast, while heavier gases give narrower curves peaking at lower speeds.
Three molecular speeds
The most probable speed lies at the peak of the Maxwell curve, the average speed is the arithmetic mean, and the root mean square speed is the square root of the mean of the squared speeds. Because the curve is skewed, they always stand in the fixed ratio 1 : 1.128 : 1.224.
Deviation of real gases
Real gases obey PV = nRT closely only at low pressure and high temperature. At high pressure the molecules occupy a significant fraction of the container and at low temperature the attractions between them can no longer be ignored, so both simplifying assumptions of the kinetic theory break down.
van der Waals equation
Written as (P + an²/V²)(V − nb) = nRT, it repairs the ideal gas equation with two constants: a measures the intermolecular attraction that lowers the observed pressure, and b is the excluded volume of the molecules themselves. Large values of a and b mark a gas that is easily liquefied.
Compressibility factor Z
Defined as Z = PV/nRT, it equals exactly 1 for an ideal gas. Z below 1 at moderate pressure shows that attractive forces make the gas more compressible than ideal, while Z above 1 at high pressure shows that molecular volume and repulsion make it harder to compress.
Critical constants and liquefaction
The critical temperature Tc is the temperature above which a gas cannot be liquefied by pressure alone; the pressure needed to liquefy it at Tc is the critical pressure Pc and the volume of one mole there is the critical volume Vc. A high Tc, as in NH₃ or SO₂, means strong attractions and easy liquefaction.
Vapour pressure and boiling point
The vapour pressure of a liquid is the pressure exerted by its vapour in equilibrium with the liquid at a given temperature, and it rises steeply with temperature. A liquid boils when its vapour pressure equals the external pressure, which is why water boils below 100 °C at high altitude.
Surface tension
Molecules at the surface of a liquid experience an unbalanced inward pull, so the liquid behaves as if covered by a stretched skin and tries to minimise its surface area. This explains spherical droplets, capillary rise and the cleaning action of detergents, and its value falls as temperature rises.
Viscosity
Viscosity is the internal resistance to flow, caused by friction between adjacent layers of a liquid moving at different speeds. Stronger intermolecular forces mean higher viscosity, so glycerol with its three hydroxyl groups is far more viscous than water, and heating always makes a liquid flow more freely.

Key formulas — States of Matter

Boyle's law
P₁V₁ = P₂V₂ at constant T and n
Charles' law
V₁/T₁ = V₂/T₂ at constant P and n, with T in kelvin
Gay-Lussac's law
P₁/T₁ = P₂/T₂ at constant V and n
Combined gas law
P₁V₁/T₁ = P₂V₂/T₂
Ideal gas equation
PV = nRT, R = 8.314 J K⁻¹ mol⁻¹ = 0.0821 L atm K⁻¹ mol⁻¹
Molar volume at STP
V(molar) = 22.4 L mol⁻¹ at 273 K and 1 atm
Molar mass from gas density
M = dRT/P, where d = mass ÷ volume
Dalton's law of partial pressures
P(total) = p₁ + p₂ + p₃ + ... and pᵢ = xᵢ × P(total)
Pressure of a gas over water
P(dry gas) = P(total) − aqueous tension
Graham's law of diffusion
r₁/r₂ = √(M₂/M₁) = √(d₂/d₁)
Root mean square speed
u(rms) = √(3RT/M), with M in kg mol⁻¹
Average and most probable speed
u(av) = √(8RT/πM), u(mp) = √(2RT/M)
Ratio of the three speeds
u(mp) : u(av) : u(rms) = 1 : 1.128 : 1.224
Average kinetic energy
KE(average per mole) = (3/2)RT
van der Waals equation
(P + an²/V²)(V − nb) = nRT
Compressibility factor
Z = PV/nRT ; Z = 1 for an ideal gas
Critical constants
Tc = 8a/27Rb, Pc = a/27b², Vc = 3b

💡 Exam tips for States of Matter

  • Every gas-law calculation must use kelvin, never Celsius. Convert first by adding 273 (or 273.15), and only then substitute into V₁/T₁ = V₂/T₂ or P₁/T₁ = P₂/T₂.
  • Pick R to match your units: 0.0821 L atm K⁻¹ mol⁻¹ when pressure is in atm and volume in litres, and 8.314 J K⁻¹ mol⁻¹ when you are computing energies or molecular speeds in SI.
  • For rms speed the molar mass must be in kg mol⁻¹, not g mol⁻¹. Using 32 instead of 0.032 for oxygen makes the answer about 31.6 times too small — a very common slip.
  • In Graham's law the square root goes with the heavier gas on top: r₁/r₂ = √(M₂/M₁). Sanity-check the answer by asking whether the lighter gas came out faster; if it did not, the ratio was inverted.
  • When a gas is collected over water, always subtract the aqueous tension before applying any gas law, otherwise you are treating the water vapour as part of the gas being measured.
  • Read Z as a diagnosis: Z < 1 means attractive forces dominate and the gas is easier to compress than ideal, while Z > 1 means molecular volume and repulsion dominate at high pressure.
  • Deviations from ideal behaviour are largest at high pressure and low temperature, that is close to the conditions under which the gas would liquefy — and a high critical temperature is the sign of a gas that liquefies easily.

Sample questions with answers & solutions

Q1Easy

The weakest intermolecular force, which is present even between the atoms of a noble gas such as argon, is

A.the hydrogen bond
B.the ion-dipole force
C.the London dispersion force✓ correct
D.the covalent bond
Why

Momentary shifts in the electron cloud create instantaneous dipoles, so London dispersion forces act between all particles, including non-polar atoms like argon.

Q2Medium

A gas occupies 500 mL at a pressure of 1 atm. At the same temperature, what volume will it occupy when the pressure is raised to 2.5 atm?

A.200 mL✓ correct
B.250 mL
C.1250 mL
D.400 mL
Why

By Boyle's law P₁V₁ = P₂V₂, so V₂ = (1 × 500)/2.5 = 200 mL. Raising the pressure 2.5 times shrinks the volume to 1/2.5 of its original value.

Q3Easy

Hydrogen bonding is possible only when hydrogen is covalently bonded to

A.carbon, sulphur or phosphorus
B.fluorine, oxygen or nitrogen✓ correct
C.chlorine, bromine or iodine
D.any metal atom
Why

F, O and N are small and highly electronegative, so the H atom bonded to them is left strongly positive and can attract a lone pair on a neighbouring F, O or N atom.

Q4Medium

A sample of gas occupies 300 cm³ at 27 °C. What volume will it occupy at 127 °C if the pressure is kept constant?

A.300 cm³
B.1410 cm³
C.225 cm³
D.400 cm³✓ correct
Why

Converting to kelvin, T₁ = 300 K and T₂ = 400 K, so V₂ = V₁ × T₂/T₁ = 300 × 400/300 = 400 cm³. Using Celsius values directly would give a wrong answer.

Q5Easy

Dipole-dipole interactions are present between the molecules of

A.H₂
B.CO₂
C.CH₄
D.HCl✓ correct
Why

HCl is a polar molecule with a permanent dipole, so its molecules attract one another end to end. H₂, CH₄ and linear CO₂ have zero net dipole moment.

Q6Medium

A gas sealed in a rigid steel cylinder exerts a pressure of 2 atm at 300 K. What pressure will it exert when the cylinder is heated to 450 K?

A.1.33 atm
B.3 atm✓ correct
C.4.5 atm
D.2.5 atm
Why

The cylinder is rigid, so volume is constant and Gay-Lussac's law applies: P₂ = P₁ × T₂/T₁ = 2 × 450/300 = 3 atm.

States of Matter — FAQs

What are the key concepts in Class 11 Chemistry States of Matter?+

Whether a substance is a gas, a liquid or a solid is decided by a tug of war between the intermolecular forces pulling its particles together and the thermal energy driving them apart. This chapter first surveys those forces — London dispersion, dipole-dipole and hydrogen bonding — and then studies the gaseous state in detail: the laws of Boyle, Charles, Gay-Lussac and Avogadro, which combine into the ideal gas equation PV = nRT, together with Dalton's law of partial pressures and Graham's law of diffusion. The kinetic molecular theory explains why these laws work and introduces the Maxwell distribution of molecular speeds. Finally, real gases are shown to deviate from ideality at high pressure and low temperature, a deviation measured by the compressibility factor and described by the van der Waals equation, which leads on to critical constants, liquefaction and the properties of the liquid state. Key ideas include London dispersion forces, Dipole-dipole interaction, Hydrogen bonding, Boyle's law, Charles' law.

What does Class 11 Chemistry Chapter 305 (States of Matter) cover on XamBaaz?+

It covers 40 NCERT-aligned MCQs on "States of Matter" — 20 Easy, 20 Medium and 0 Hard — each with a timed quiz and an instant explanation, suitable for CBSE Board exams, JEE Main, JEE Advanced and NEET UG.

Are these "States of Matter" questions free to practise?+

Yes — sign in with Google to practise "States of Matter" free. Full unlimited access is ₹999/year (limited-time launch price), with no per-chapter charges.

How should I revise "States of Matter" for the exam?+

Start with the Easy quiz to confirm your fundamentals, then attempt Medium and Hard for application-level practice. Review each explanation, retry the questions you miss, and track your accuracy on this chapter until it is consistently high.

Are these "States of Matter" MCQs available with answers?+

Yes. The sample questions on this page show the correct option and a "Why" explanation right away — no sign-in needed to read them. Sign in free to attempt all 40 questions with instant scoring.

Is there negative marking in the "States of Matter" quizzes?+

Yes — the timed quizzes use exam-grade marking: +4 for a correct answer, −1 for a wrong one and 0 for a skipped question, so you practise the same negative-marking discipline as CBSE Board exams, JEE Main, JEE Advanced and NEET UG.

Are these important questions for States of Matter?+

The set is curated to the NCERT syllabus and weighted toward the question patterns that actually appear in CBSE Board exams, JEE Main, JEE Advanced and NEET UG, across Easy, Medium and Hard — so it doubles as an "important questions" revision list for "States of Matter".

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